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12 July, 02:28

The K w for water at 0 ∘ C is 0.12 * 10 - 14. Calculate the pH of a neutral aqueous solution at 0 ∘ C.

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  1. 12 July, 06:21
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    pH = 7.46

    Explanation:

    2H₂O ⇄ H₃O⁺. OH⁻ Kw = [H₃O⁺]. [OH⁻]

    [H₃O⁺] = [OH⁻]

    √0.12*10⁻¹⁴ = [H₃O⁺] → 3.46*10⁻⁸ M

    - log [H₃O⁺] = pH

    - log 3.46*10⁻⁸ = pH → 7.46
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