An enclosed cylinder has 3.00 moles of gas with a volume of 60.0 L and a temperature of 400.0 K. What is the pressure inside the cylinder?

The answer to your question is: 1.64 atm

Explanation:

Data

n = 3 moles

v = 60 l

T = 400 °K

P = ?

R = 0.082 atml/mol°K

Formula

PV = nRT (ideal gas formula)

clear P from this equation

P = nRT/V

P = 3 (0.082) (400) / 60 substitution

P = 98.4 / 60 process

P = 1.64 atm. result