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29 September, 10:16

A chemist adds 295.0 mL of a 0.221M barium chlorate (Ba (ClO3) 2) solution to a reaction flask. Calculate the millimoles of barium chlorate the chemist has added to the flask. Round your answer to 3 significant digits.

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  1. 29 September, 13:27
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    65.2

    Explanation:

    For this task, we will use formula C = n/V,

    where C is molar concentration (amount of substance per unit volume). The most commonly used unit for molarity is the number of moles per litre with the unit symbol mol/L, or differently M

    n is the amount of substance. The most commonly used unit for the amount of substance is mole with the unit symbol mol

    V is the volume of substance. The most commonly used unit for the volume is dm3 which equals to 1L - liter.

    In the task we were given the following information:

    V = 295.0 mL = 0.2950 L

    C = 0.221 M

    n = ?

    C = n/V ⇒ n = C x V

    n = 0.2950 L x 0.221 mol/L

    n = 0.065195 mole

    We will now transform moles to millimoles because we need to calculate the millimoles of barium chlorate

    1 mole = 1000 millimoles ⇒ 0.065195 moles = 65.195

    Now, we only need to round this answer to 3 significant digits, so the answer would be 65.2
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