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7 April, 23:05

If 0.220 molmol of a nonvolatile nonelectrolyte are dissolved in 3.70 molmol of water, what is the vapor pressure PH2OPH2O of the resulting solution? The vapor pressure of pure water is 23.8 torrtorr at 25 ∘C∘C.

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  1. 8 April, 01:54
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    Vapor pressure for solution is 22.4 Torr

    Explanation:

    P° → Vapor pressure of pure solvent

    P' → Vapor pressure of solution

    Formula for lowering vapor pressure is: P° - P' = P°. Xm

    Xm is the mole fraction. Let's determine it:

    0.220 mol of solute + 3.70 mol of water = 3.92 total moles

    Mole fraction for solute → 0.220 / 3.92 = 0.056

    23.8 Torr - P' = 23.8 Torr. 0.056

    P' = - (23.8 Torr. 0.056 - 23.8 Torr) → 22.4 Torr
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