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13 August, 23:30

The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (KHP).

In the titration, 20.46 mL of the NaOH solution was required to react with 0.1082g KHP.

Calculate the molarity of the base.

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  1. 14 August, 02:36
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    [ NaOH ] = 0.026 M

    Explanation:

    molarity NaOH = mol NaOH / Vsln (L)

    ∴ Vsln = 20.46 mL = 0.02046 L

    NaOH (aq) + KHC8H4O4 (aq) → KNaC8H4O4 (aq) + H2O (l)

    ∴ Mw KH (KHC8H4O4) = 204.24 g/mol

    ⇒ mol KHP = 0.1082 g / 204.24 g/mol = 5.298 E-4 mol

    ⇒ mol NaOH = (5.298 E-4 mol KHP) (mol NaOH/mol KHP)

    ⇒ mol NaOH = 5.298 E-4 mol

    ⇒ [ NaOH ] = 5.298 E-4 mol / 0.02046 L

    ⇒ [ NaOH ] = 0.026 mol/L = 0.026 M
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