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26 November, 16:44

What mass of ammonia will exert the same pressure as 12.8 mg of hydrogen sulfide (H2S) in the same container under the same conditions?

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  1. 26 November, 20:37
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    There will 6.38 mg of NH3 extert the same pressure as 12.8 mg H2S

    Explanation:

    Step 1: Data given

    Mass of hydrogen sulfide (H2S) = 12.8 mg = 0.0128 grams

    Molar mass of H2S = 34.1 g/mol

    Step 2: Calculate moles of H2S

    Moles of H2S = Mass H2S / molar mass H2S

    Moles H2S = 0.0128 grams / 34.1 g/mol

    Moles H2S = 3.75 * 10^-4

    Gases here, exert exacty the same amount of pressure per mole as any other gas.

    The ammonia will exert the same pressure as the hydrogen sulfide when the moles of ammonia equal the moles of hydrogen sulfide

    Step 3: Calculate moles of NH3

    Moles of H2S = moles of NH3

    moles of NH3 = 3.75 * 10^-4

    Step 4: Calculate mass of NH3

    Mass of NH3 = moles NH3 * molar mass NH3

    Mass of NH3 = 3.75 * 10^-4 moles * 17.03 g/mol

    Mass of NH3 = 0.00639 grams = 6.38 mg

    There will 6.38 mg of NH3 extert the same pressure as 12.8 mg H2S
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