A blacksmith making a tool heats 525 grams of steel to 1230C. After hammering the steel, she places it into a bucket of water to cool it. When she removes the steel from the water, it's a 50C. How much heat does the steel release if its specific heat capacity is 0.486 joules/gram degree celsius?

Q = 18625.95 j

Explanation:

Given dа ta:

Mass of steel = 525 g

Initial temperature = 123 °C

Final temperature = 50 °C

Heat release by steel = ?

Specific heat capacity of steel = 0.486 j/g. °C

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 123°C - 50°C

ΔT = 73°C

Q = m. c. ΔT

Q = 525 g. 0.486 j/g.°C. 73°C

Q = 18625.95 j