A solution is made by mixing 24. G of acetyl bromide (CH3COBr) and 18. G of heptane (C7H16). Calculate the mole fraction of acetyl bromide in this solution

The mol fraction of acetyl bromide is 0.52

Explanation:

Step 1: Data given

Mass acetyl bromide = 24.0 grams

Molar mass of acetyl bromide = 122.95 g/mol

Mass of heptane = 18.0 grams

Molar mass of heptane = 100.21 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles acetyl bromide = mass acetyl bromide / molar mass acetyl bromide

Moles acetyl bromide = 24.0 grams / 122.95 g/mol

Moles acetyl bromide = 0.195 moles

Moles heptane = 18.0 grams / 100.21 g/mol

Moles heptane = 0.180 moles

Step 3: Calculate total moles

Total moles = 0.195 moles + 0.180 moles

Total moles = 0.375 moles

Step 4: Calculate mol fraction of acetyl bromide

Mol fraction acetyl bromide = moles acetyl bromide / total moles

Mol fraction acetyl bromide = 0.195 moles / 0.375 moles

Mol fraction acetyl bromide = 0.52

The mol fraction of acetyl bromide is 0.52

Mole fraction of acetyl bromide → 0.52

Explanation:

To determine the mole fraction, we must need to convert the mass to moles.

Mole fraction = Moles of solute or solvent / Total moles

Moles of acetyl bromide = 24 g / 122.9 g/mol = 0.195 moles

Moles of heptane = 18 g / 100 g/mol = 0.18 moles

Total moles = moles of heptane + moles of acetyl bromide

0.18 + 0.195 = 0.375 → Total moles

Mole fraction of acetyl bromide = 0.195 / 0.375 = 0.52