Pure acetic acid has a density of 1.049g / (ml). Calculate the molarity of a solution of acetic acid made by dissolving 20.00 ml in enough water to make 250.0 ml of solution

Molarity = 1.4 M

Explanation:

Given dа ta:

Density of acetic acid = 1.049 g/mL

Volume of acetic acid = 20.0 mL

Volume of solution = 250.0 mL (250/1000 = 0.25 L)

Molarity = ?

Solution:

Mass of acetic acid = density * volume

Mass of acetic acid = 1.049 g/mL * 20.0 mL

Mass of acetic acid = 20.98 g

Number of moles of acetic acid = mass / molar mass

Number of moles of acetic acid = 20.98 g / 60.052 g/mol

Number of moles of acetic acid = 0.35 mol

Molarity = number of moles / volume in L

Molarity = 0.35 mol / 0.25 L

Molarity = 1.4 M