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29 October, 14:13

100.0 grams of sucrose (C12H22O11) is dissolved in 1.50 L of water. What is the molality?

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  1. 29 October, 15:50
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    Molality = 66.67g/L

    Explanation:

    Mass of sucrose = 100g

    Volume of water = 1.50L

    Molality = mass of substance / volume in L

    Molality = 100 / 1.50

    Molality = 66.67g/L

    Molality of 100g of sucrose in 1.50L of water is 66.67g/L
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