At 1250 mmHg and 750C, the volume of a sample of ammonia gas is 6.8 L. What volume would the ammonia occupy at STP?

V₂ = 3 L

Explanation:

Given dа ta:

Initial volume = 6.8 L

Initial pressure = 1250 mmHg (1250/760 = 1.64 atm)

Initial temperature = 750°C (750 + 273 = 1023 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂ / T₁ P₂

V₂ = 1.64 atm * 6.8 L * 273 K / 1023 K * 1 atm

V₂ = 3044.5 atm. L. K / 1023 K. atm

V₂ = 3 L