Calculate the amount of heat liberated (in kJ) from 345 g of mercury when it cools from 72.7°C to 12.0°C.

2.93181 Kj

Explanation:

Given dа ta:

Mass of mercury = 345 g

Initial temperature = 72.7°C

Final temperature = 12.0°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of mercury = 0.14 j/g.°C

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT = 12.0°C - 72.7°C

ΔT = - 60.7°C

Q = m. c. ΔT

Q = 345 g * 0.14 j/g.°C * - 60.7°C

Q = - 2931.81 j

Joule to Kj conversion:

2931.81 j * 1 kj / 1000 j = 2.93181 Kj