A quantity of gas has a volume if 400.0 ml when confined under a pressure of 600.0mm Hg. What will be the new volume of the gas if the pressure is reduced to 200.0 mm Hg at constant temperature

1200 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 400 mL.

Initial pressure (P1) = 600 mmHg.

Final volume (V2) = ... ?

Final pressure (P2) = 200 mmHg

Step 2:

Determination of the final volume i. e the new volume of the gas.

Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:

P1V1 = P2V2

600 x 400 = 200 x V2

Divide both side by 200

V2 = (600 x 400) / 200

V2 = 1200 mL

Therefore, the new volume of the gas is 1200 mL.