0.7 L of H2 enters a reaction at standard temperature and pressure.

How many particles of H2 reacted?

2.69 x 1022 particles H2

1.88 x 1022 particles H2

1.35 x 1025 particles H2

4.21 x 1023 particles H2

1.88 * 10²³ particles

Explanation:

Given dа ta:

Volume of H₂ = 0.7 L

Number of particles at STP = ?

Solution:

First of all we will calculate the number of moles of H₂.

PV = nRT

n = PV / RT

n = 1 atm. 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ * 273.15 K

n = 7 atm. L / 22.43 L. atm. mol⁻¹

n = 0.312 mol

it is known that,

2 g H₂ = 1 mol = 6.022 * 10²³ particles

For 0.312 mol

0.312 * 6.022 * 10²³ particles

1.88 * 10²³ particles