An apparatus consists of a 4.0 dm3 flask containing nitrogen gas at 25 oC and 803 kPa. It is joined by a valve to a 10.0 dm3 flask containing argon gas 25 oC and 47.2 kPa. The valve is opened and the gases mix. i. What is the partial pressure of each gas after mixing?

Partial pressure of nitrogen = 229.43 kpa

Partial pressure of argon = 33.7 Kpa

Explanation:

Given dа ta:

Volume of flask one = 4.0 dm³

Temperature = 25°C

Pressure of nitrogen = 803 KPa

Final volume = 4.0 dm³ + 10.0 dm³ = 14.0 dm³

Initial volume of argon = 47.2 KPa

Final pressure of both gases when valve is open = ?

Solution:

For nitrogen:

P₁V₁ = P₂V₂

803 KPa * 4 dm³ = P₂ * 14.0 dm³

P₂ = 803 KPa * 4 dm³ / 14.0 dm³

P₂ = 3212 kpa / 14.0

P₂ = 229.43 kpa

For argon:

P₁V₁ = P₂V₂

47.2 KPa * 10.0 dm³ = P₂ * 14.0 dm³

P₂ = 47.2 KPa * 10.0 dm³/14.0 dm³

P₂ = 472 kpa / 14.0

P₂ = 33.7 Kpa