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14 July, 19:08

Combining 0.380 mol Fe2O3 with excess carbon produced 13.7 g Fe

Fe2O3 + 3C → 2Fe + 3CO

What is the actual yield of iron in moles?

What is the theoretical yield of iron in moles?

What is the percent yield?

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Answers (1)
  1. 14 July, 20:21
    0
    Percent yield = 32.9%

    Explanation:

    Given dа ta:

    Number of moles of Fe₂O₃ = 0.380 mol

    Number of moles of Fe produced = 13.7 g

    Theoretical yield = ?

    Actual yield of iron in mol = ?

    Percent yield = ?

    Solution:

    Chemical equation:

    Fe₂O₃ + 3C → 2Fe + 3CO

    Actual yield of iron in moles:

    Number of moles = mass / molar mass

    Number of moles = 13.7 g / 55.8 g/mol

    Number of moles = 0.25 mol

    Theoretical yield:

    Fe₂O₃ : Fe

    1 : 2

    0.380 : 2*0.380 = 0.76

    Theoretical yield = 0.76 mol

    Percent yield:

    Percent yield = actual yield / theoretical yield * 100

    Percent yield = 0.25 mol / 0.76 mol * 100

    Percent yield = 32.9%
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