Find the empirical formula for a compound consisting of 63% Mn and 37% 0

Empirical formula is MnO₂

Explanation:

Given dа ta:

Percentage of Manganese = 63%

Percentage of oxygen = 37%

Empirical formula = ?

Solution:

Number of gram atoms of Mn = 63 / 55 = 1.1

Number of gram atoms of O = 37 / 16 = 2.3

Atomic ratio:

Mn : O

1.1/1.1 : 2.3/1.1

1 : 2.1

Mn : O = 1 : 2

Empirical formula is MnO₂.