A solution of bleach has about 1.5 g of NaOCl dissolved in 220 mL of solution. What is the molarity?

0.091 mol/L

Explanation:

Molarity of a substance, is the number of moles present in a liter of solution.

M = n / V

M = molarity (unit = mol / L or M)

V = volume of solution in liter (unit = L),

n = moles of solute (unit = mol),

Moles is denoted by given mass divided by the molecular mass,

Hence,

n = w / m

n = moles,

w = given mass,

m = molecular mass.

From the data of the question, it is given that,

w = 1.5 g

V = 220 mL

Since,

1 mL = 1/1000L

V = 0.220 L

As we known, the mass of bleach NaOCl is,

m = 74.44 g/mol

from the above equation, moles can be calculated as -

n = w / m

n = 1.5g / 74.44 g/mol

n = 0.0201 mol

Molarity of the solution is calculated as,

M = n / V

M = 0.0201 mol / 0.220 L

M = 0.091 mol/L