An 85-g sample of iron is at an initial temperature of 38 °C. If 2213 joules of heat are applied to the sample, what is the final temperature of the iron?

The final temperature of the iron is 95.86 °C

Explanation:

To solve the question we must first find out the specific heat of iron which is 0.450 J/g°C

Then we list out the known variables

Initialtemperature = 38 °C

Applied heat = 2213 joules

Mass of sample = 85 g

Therefore, the required formula relating the final temperature of the iron to the known variables is

ΔH = m·C·Δθ where ΔH = applied heat, m = mass, C = specific heat capacity

plugging in the values we have

2213 J = 85 g*0.450 J/g° C * (T₂ - 38 °C), where T₂ = The final temperature of the iron

2213 J - 1453.5 J = 38.25 * T₂ or T₂ = 95.86 °C

The final temperature of the iron is 95.86 °C