How many grams are in 1 mole of Pb3 (PO4) 4?

In 1 mol of Pb₃ (PO₄) ₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2.3 = 621.6 g/m

P = 30.97.4 = 123.88 g/m

O = (16. 4). 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

Molar mass of Pb3 (PO4) 4 is 380+621.6 = 1001.6 g/mole

Molar comcentration = Reacting mass / Molar Mass

1 = Mr/1001.6

Mr = 1001.6g