Determine the total pressure of a mixture of 0.400 mole of He and 0.600 mole of Ne in a 2.00 liter container at 25oC.

Question

Chemistry

Haylie Norris

17 May, 15:03

Determine the total pressure of a mixture of 0.400 mole of He and 0.600 mole of Ne in a 2.00 liter container at 25oC.

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Answers (1)

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Jonah Odom · Answer 1

Total pressure of the mixture is 12.2 atm

Explanation:

Let's apply the Ideal Gases law to solve this

Total pressure. V = Total moles. R. T

Total moles = 0.4 m of He and 0.6 mole of Ne → 1 mol

P. 2L = 1 mol. 0.082 L. atm/mol. K. 298K

P = (1 mol. 0.082 L. atm/mol. K. 298K) / 2L

P = 12.2 atm