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17 May, 15:03

Determine the total pressure of a mixture of 0.400 mole of He and 0.600 mole of Ne in a 2.00 liter container at 25oC.

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  1. 17 May, 17:20
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    Total pressure of the mixture is 12.2 atm

    Explanation:

    Let's apply the Ideal Gases law to solve this

    Total pressure. V = Total moles. R. T

    Total moles = 0.4 m of He and 0.6 mole of Ne → 1 mol

    P. 2L = 1 mol. 0.082 L. atm/mol. K. 298K

    P = (1 mol. 0.082 L. atm/mol. K. 298K) / 2L

    P = 12.2 atm
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