The density of a metal is 10.5 g/cm3. If the mass of themetal

is 5.25 g and it is placed in 11.2 ml of water, how much willthe

water rise?

11.7 mL

Explanation:

Density of a substance is given by the mass of the substance divided by the volume of the substance.

Hence, d = m / V

V = volume

m = mass,

d = density,

From the question,

The density of the metal = 10.5 g/cm³

The mass of the metal = 5.25 g

Hence, the volume can be calculated from the above formula, i. e.,

d = m / V

V = m / d

V = 5.25 g / 10.5 g/cm³

V = 0.5 cm³

Since, The unit 1 mL = 1 cm³

V = 0.5 mL

The vessel has 11.2 mL of water,

The new volume becomes,

11.2 mL + 0.5 mL = 11.7 mL