Consider water at 1400 kPa and 200 C. What is the specific volume (in m3 / kg) ?

Vw = 2.80907 E-3 m³/Kg

Explanation:

specific volume is the inverse of density:

⇒ Vw = 1 / ρ

∴ water at:

⇒ P = 1400 KPa * (1000 Pa / KPa) = 1400000 Pa

⇒ T = 200°C = 473 K

Water at these conditions is found as saturated steam, specific volume would be:

⇒ Vw = R*T / P

∴ R = 8.3144 Pa. m³ / Kg. K

⇒ Vw = ((8.3144) * (473)) / 1400000

⇒ Vw = 2.80907 E-3 m³/Kg