What is the concentration in molarity of an aqueous solution which contains 5.21% by mass ethylene glycol (mm=62.07g/mol) ? The density of the solution is 1.04g/ml.

C C2H6O2 = 0.873 M

Explanation:

Molarity [=] mol / L wt% = (g C2H6O2 / g sln) * 100

⇒ 0.0521 = g C2H6O2 / g sln

∴ mm C2H6O2 = 62.07 g/mol

∴ δ sln = 1.04 g/mL

assuming: g sln = 1 g

⇒ g C2H6O2 = 0.0521 g

⇒mol C2HJ6O2 = (0.0521 g) (mol/62.07 g) = 8.394 E-4 mol C2H6O2

⇒ V sln = 1g sln / 1.04 g/mL = 0.9615 mL = 9.615 E-4 L sln

⇒ C C2H6O2 = (8.394 E-4 mol) / (9.615 E-4 L sln)

⇒ C C2H6O2 = 0.873 mol/L