Calculate the value of K p for the equation C (s) + CO 2 (g) - ⇀ ↽ - 2 CO (g) K p = ? given that at a certain temperature C (s) + 2 H 2 O (g) - ⇀ ↽ - CO 2 (g) + 2 H 2 (g) K p 1 = 3.23 H 2 (g) + CO 2 (g) - ⇀ ↽ - H 2 O (g) + CO (g) K p 2 = 0.693

kp = 1.55

Explanation:

To get to this reaction, we just need to sum the other two reactions, and multiply coefficients if it's needed so:

C (s) + 2H₂O (g) ⇄CO₂ (g) + 2H₂ (g) Kp1 = 3.23 (1)

H₂ (g) + CO₂ (g) ⇄ H₂O (g) + CO (g) Kp2 = 0.601 (2)

we will multiply eqn 2 by 2 because we need to eliminate H₂

2H2 (g) + 2CO2 (g) ⇄ 2H2O (g) + 2CO (g) Kp = (0.601) ²

Now, add both equation

C (s) + 2H₂O (g) ⇄CO₂ (g) + 2H₂ (g) Kp1 = 3.23

2H2 (g) + 2CO2 (g) ⇄ 2H2O (g) + 2CO (g) Kp = (0.601) ²

we have,

C (s) + CO₂ (g) ⇄ 2CO (g)

Now the value of Kp will be:

kp = 3.23 * (0.693) ²

kp = 1.55