What is the volume of the air in a balloon that occupies 0.620 L at 25*C if the temperature is lowered to 0.00 * C. (assuming the pressure remains constant)

0.568L

Explanation:

V1 = 0.620 L

T1 = 25°C = 25 + 273 = 298K

V2 = ?

T2 = 0°C = 273K

V1 / T1 = V2 / T2

0.620/298 = V2 / 273

Cross multiply

298 x V2 = 0.620 x 273

Divide both side by the coefficient V2 ie 298, we have

V2 = (0.620 x 273) / 298

V2 = 0.568L

Therefore, the volume of the air when the temperature is reduced to 0°C is 0.568L