how much heat will be absorbed by 25g of chloroform when its temperature started at 67.0C and after it was 112.0C

Q = 1102.5 j

Explanation:

Given dа ta:

Mass of chloroform = 25 g

Initial temperature = 67.0°C

Final temperature = 112.0°C

Heat absorbed = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of chloroform = 0.98 j/g.°C

ΔT = T2-T1

ΔT = 112.0°C - 67.0°C

ΔT = 45°C

Q = m. c. ΔT

Q = 25 g * 0.98 j/g.°C * 45°C

Q = 1102.5 j