An open-end manometer containing mercury was connected to a vessel holding a gas at a pressure of 767 torr. The atmospheric pressure was 724 torr. What is the difference in the heights of the mercury, expressed in cm?

h = 4.32 cm

Explanation:

P = Patm + δHg*g*h

∴ P = 767 torr

∴ Patm = 724 torr

∴ δ Hg = 13534 Kg/m³

∴ g = 9.8 m/s²

⇒ h = (767 torr - 724 torr) / ((13534 Kg/m³) (9.8 m/s²))

⇒ h = 43 torr / 132633.2 Kg/m²s² = 5732.86 Pa / 132633.2 Kg/m²s²

∴ Pa ≡ Kg/ms²

⇒ h = 0.0432 m = 4.32 cm