A solution is made by mixing 127. g of acetyl bromide CH3COBr and 90. g of heptane C7H16. Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 3 significant digits.

The mole fraction of acetyl bromide is 0.535

Explanation:

Step 1: Data given

Mass of acetyl bromide = 127 grams

Mass of heptane = 90 grams

Molar mass of acetyl bromide = 122.95 g/mol

Molar mass of heptane = 100.21 g/mol

Step 2: Calculate moles acetyl bromide

Moles acetyl bromide = mass acetyl bromide / molar mass acetyl bromide

Moles acetyl bromide = 127.0 grams / 122.95 g/mol

Moles acetyl bromide = 1.033 moles

Step 3: Calculate moles heptane

Moles heptane = 90.0 grams / 100.21 g/mol

Moles heptane = 0.898 moles

Step 4: Calculate Total moles

Total moles = moles acetyl bromide + moles heptane

Total moles = 1.033 moles + 0.898 moles

Total moles = 1.931 moles

Step 5: Calculate the mole fraction of acetyl bromide

Mole fraction acetyl bromide = 1.033 moles / 1.931 moles

Mole fraction acetyl bromide = 0.535

The mole fraction of acetyl bromide is 0.535