If the temperature of a 95.00g sample of Iron started at 36.0 degrees C and ended at 58 degrees C how much heat would be lost?

Q = 940.5 j

Explanation:

Given dа ta:

Mass of iron = 95.00 g

Initial temperature = 36.0°C

Final temperature = 58°C

Heat lost = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of iron = 0.450 j/g.°C

ΔT = T2-T1

ΔT = 58°C-36.0°C

ΔT = 22°C

Q = m. c. ΔT

Q = 95.00 g * 0.450 j/g.°C * 22°C

Q = 940.5 j