In the 1 H NMR spectrum of chloroethane the methylene group is split into a quartet by the α and β nuclear spins of the protons on the neighboring methyl group. If the external magnetic field, Bo, directs upward, which sequence of nuclear spins contributes to the second farthest peak downfield within the spin-spin splitting pattern?

Question

Chemistry

Mercedes Shelton

8 August, 12:59

In the 1 H NMR spectrum of chloroethane the methylene group is split into a quartet by the α and β nuclear spins of the protons on the neighboring methyl group. If the external magnetic field, Bo, directs upward, which sequence of nuclear spins contributes to the second farthest peak downfield within the spin-spin splitting pattern?

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Diamond Montoya · Answer 1

Answer:+1/2 and - 1/2.

Explanation:the presence of an external magnetic field (B0), two spin states exist, + 1/2 and - 1/2.

The magnetic moment of the lower energy + 1/2 state is aligned with the external field, but that of the higher energy - 1/2 spin state is opposed to the external field.