Calculate the milligrams of chlorine (35.453 g/mol) in a 3.44 g solution of 18.0 wt% CaCl2 (110.98 g/mol).

395 mg of Cl are in 3.44 g of CaCl₂

Explanation:

18.0 wt% CaCl₂ means that 18 g of salt, are contained in 100 g of solvent (assuming solvent as solution).

Let's apply a rule of three:

In 100 g of solution we have 18 g of salt

In 3.44 g of solvent we have (3.44.18) / 100 = 0.1692 grams of salt.

Now, let's convert this mass into moles (mass / molar mass)

0.1692 mass / 110.98 g/m = 0.00558 moles

1 mol of CaCl₂ has 1 mol of Ca and 2 moles of Cl

Then, 0.00558 moles of CaCl₂, would have the double of moles of Cl

0.00558 m. 2 = 0.01116 moles of Cl.

Let's convert the moles into mass (mol. molar mass)

0.01116 moles of Cl. 35.453g/m = 0.395 grams of Cl.

Finally we convert grams to mg (x1000)

0.395 g = 395 mg