How many molecules are in 1.00 g of C10H14N2? 3.71 x 1021 9.76 x 1025 1.02 x 10-26 2.32 x 1022

3.71 x 1021 (First option)

Explanation:

Let's determine the molar mass of the compound.

C₁₀H₁₄N₂ = 12. 10 + 14.1 + 14.2 = 162 g/mol

So 162 grams of compound are contained in 1 mol

1 g of C₁₀H₁₄N₂ are contained in (1 / 162) = 0.00617 moles

Let's conver the moles into amount of molecules (mol. NA)

0.00617. 6.02*10²³ = 3.71*10²¹ molecules