Aluminum bromide reacts with chlorine gas to produce aluminum chloride and liquid bromide,

according to the chemical equation below:

2A1Br3 + 3Cl2 + 2AlCl3 + 3Br2

How many moles of Aluminum chloride are made if 779 g of chlorine gas are consumed?

779 g of chlorine would produce 7.3 moles of AlCl₃

Explanation:

Given dа ta:

Mass of chlorine gas = 779 g

Number of moles of Aluminium chloride formed = ?

Solution:

Chemical equation:

2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂

Number of moles of chlorine:

Number of moles = mass / molar mass

Number of moles = 779 g / 71 g/mol

Number of moles = 11 mol

Now we will compare the moles of chlorine with Aluminium chloride.

Cl₂ : AlCl₃

3 : 2

11 : 2/3*11 = 7.3 mol

779 g of chlorine would produce 7.3 moles of AlCl₃.