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25 December, 04:32

Calculate the specific heat of a piece of wood if 1500 grams of the wood absorbs

67,500 Joules of heat and its temperature changes from 32 °C to 57 °C.

0.18 J/g °C

1.2 J/g °C

1.8 J/g °C

0.48 J/g °C

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  1. 25 December, 07:16
    0
    Specific heat capacity of wood = 1.8 j/g. °C

    Explanation:

    Given dа ta:

    Mass of wood = 1500 g

    Heat absorbed = 67500 j

    Initial temperature = 32 °C

    Final temperature = 57 °C

    Specific heat capacity = ?

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = 57 - 32°C = 25°C

    Q = m. c. ΔT

    67500 j = 1500 g * c * 25°C

    67500 j = 37500 g. °C * c

    67500 j / 37500 g. °C = c

    c = 1.8 j/g. °C

    Specific heat capacity of wood is 1.8 j/g. °C.
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