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26 May, 14:33

A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equation to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm

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  1. 26 May, 18:00
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    Answer: 91.73g of NaCl

    Explanation:

    First, we solve for the number of moles of F2 using the ideal gas equation

    V = 12L

    P = 1.5 atm

    T = 280K

    R = 0.082atm. L/mol/K

    n = ?

    PV = nRT

    n = PV / RT

    n = (1.5x12) / (0.082x280)

    n = 0.784mol

    Next, we convert this mole (i. e 0.784mol) of F2 to mass

    MM of F2 = 19x2 = 38g/mol

    Mass conc of F2 = n x MM

    = 0.784 x 38 = 29.792g

    Equation for the reaction is given below

    F2 + 2NaCl - > 2NaF + Cl2

    Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

    Mass conc. of NaCl from the equation = 2 x 58.5 = 117g

    Next, we find the mass of NaCl that reacted with 29.792g of F2.

    From the equation,

    38g of F2 redacted with 117g of NaCl.

    Therefore, 29.792g of F2 will react with Xg of NaCl i. e

    Xg of NaCl = (29.792 x 117) / 38

    = 91.73g

    Therefore, 91.73g of NaCl reacted with f2
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