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16 January, 03:59

Determine the temperature (in K) of 1.5 moles of gas contained in a 5.5 L vessel at a pressure of 192.4 kPa.

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  1. 16 January, 05:30
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    84.96K

    Explanation:

    The following were obtained from the question:

    n = 1.5 mole

    V = 5.5L

    P = 192.4 kPa = 192400Pa

    Recall

    101325Pa = 1atm

    192400Pa = 192400/101325 = 1.9atm

    R = 0.082atm. L/K / mol

    T=?

    We can obtain the temperature by applying the following:

    PV = nRT

    T = PV / nR

    T = (1.9 x 5.5) / (1.5 x 0.082)

    T = 84.96K
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