Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of licl in 13.7 moles of h2o.

Molality is 0.45 mol/kg for the LiCl

Explanation:

Molality → Moles of solute in 1kg of solvent

Let's convert the moles of solvent, water to mass (g)

Afterwards we need to convert the mass from g to kg

Molality → mol / kg

First step: 13.7 mol. 18 g / 1mol = 246.6 g

2nd step: 246.6 g. 1kg / 1000 g = 0.2466 kg

Molality → mol/kg → 0.112 moles / 0.2466 kg → 0.45 molal