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17 November, 07:05

What is the molarity of a aqueous solution of potassium hydroxide (KOH, 56.106 g/mol) if the molality of the solution is 5.2 mol/kg

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  1. 17 November, 10:24
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    The molarity is 8.52M

    Explanation:

    molality = moles of solute/kg of solvent = 5.2mol/kg

    moles of solute = 5.2mole

    mass of solute = moles of solute * MW = 5.2 * 56.106 = 291.8g

    mass of solvent = 1kg = 1000g

    mass of solution = mass of solute + mass of solvent = 291.8g + 1000g = 1291.8g

    Density of KOH = 2120g/L

    Volume of solution = mass/density = 1291.8/2120 = 0.61L

    Molarity = number of moles of solute/volume of solution = 5.2/0.61 = 8.52M
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