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13 November, 02:45

A student tries to make diphosphorus trioxide using the reaction below. He adds exactly 20.00 grams of Phosphorus to an excess of oxygen gas. Calculate the theoretical yield of how much P2O3 will be made

P4 (s) + O2 (g) - -> P2O3 (s)

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  1. 13 November, 06:06
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    Mass = 87.952 g

    Explanation:

    Given dа ta:

    Mass of phosphorus = 20.0 g

    Theoretical yield of P₂O₃ = ?

    Solution:

    Chemical equation:

    P₄ + 3O₂ → 2P₂O₃

    Number of moles of phosphorus:

    Number of moles = mass / molar mass

    Number of moles = 20.0 g / 123.9 g/mol

    Number of moles = 0.2 mol

    Now we will compare the moles of phosphorus with P₂O₃.

    P₄ : P₂O₃

    1 : 2

    0.2 : 2/1*0.2 = 0.4 mol

    Theoretical yield:

    Mass = number of moles * molar mass

    Mass = 0.4 mol * 219.88 g/mol

    Mass = 87.952 g
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