An aqueous solution of 14.7 g of catalase, an enzyme found in the liver, has a volume of 1.00 L at 27oC. The solution's osmotic pressure at 27oC is found to be 1.10 torr. Calculate the molar mass of catalase

2.49*10⁵ g/mol will be the molar mass for catalase

Explanation:

Osmotic pressure formula, to be applied here:

π = M. R. T

We convert the π from torr to atm → 1.10 torr. 1atm / 760 atm = 1.45*10⁻³ atm

We convert T°, from °C to K → 27°C + 273 = 300K

We replace data given → 1.45*10⁻³ atm = M. 0.082 L. atm/mol. K. 300K

M = 1.45*10⁻³ atm / 0.082 L. atm/mol. K. 300K → 5.89*10⁻⁵ moles

As the volume of catalase is 1L, we asume the found moles to be contained in 14.7 g so let's find molar mass now:

14.7g / 5.89*10⁻⁵ mol = 2.49*10⁵ g/mol