What is the ph of a solution that results from mixing 25 ml of 0.15 M hcl to 25 ml of 0.52 m nh3?

7.00

Explanation:

When the solutions are mixed, the HCl dissociates to form the ions H + and Cl-. The ion H + will react with the NH3 to form NH4+. The stoichiometry for this is 1 mol of HCl to 1 mol of H + to 1 mol of Cl-, and 1 mol of H + to 1 mol of NH3 to 1 mol of NH4+.

First, let's find the number of moles of each one of them, multiplying the concentration by the volume:

nH + = 0.15 M * 25 mL = 3.75 mmol

nNH3 = 0.52 M * 25 mL = 13 mmol

So, all the H + is consumed, and the neutralization is completed, thus pH will be the pH of the solvent (water), pH = 7.00.