Ask Question
17 April, 21:30

The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58 cal of heat.

+4
Answers (1)
  1. 18 April, 01:12
    0
    22.27 °C = ΔT

    Explanation:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m * c * ΔT

    Given dа ta:

    mass = 28 g

    heat absorbed = 58 cal

    specific heat of copper = 0.093 cal/g.°C

    temperature change = ΔT=?

    Solution:

    Q = m * c * ΔT

    58 cal = 28 g * 0.093 cal / g.°C * ΔT

    58 cal = 2.604 cal.°C * ΔT

    58 cal / 2.604 cal.°C = ΔT

    22.27 °C = ΔT
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58 cal of ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers