A carbon forms one bond to an X atom plus three more bonds to three hydrogen atoms. If the hybridization to X has 81% p-character, what is the H-C-X bond angle in degrees to the nearest tenth of a degree?

110 degree

Explanation:

This is because Hybridization of an s orbital with all three p orbitals (px, py, and pz) results in four sp3 hybrid orbitals. sp3 hybrid orbitals are oriented at bond angle of 109.5 degrees from each other. This 109.5 degrees gives an arrangement of tetrahedral geometry