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29 December, 05:40

A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the temperature of the gas in the container?

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  1. 29 December, 09:20
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    56972.17K

    Explanation:

    P = 4.06kPa = 4.06*10³Pa

    V = 14L

    n = 0.12 moles

    R = 8.314J/Mol. K

    T = ?

    We need ideal gas equation to solve this question

    From ideal gas equation,

    PV = nRT

    P = pressure of the ideal gas

    V = volume the gas occupies

    n = number of moles

    R = ideal gas constant

    T = temperature of the gas

    PV = nRT

    T = PV / nR

    T = (4.06*10³ * 14) / (0.12 * 8.314)

    T = 56840 / 0.99768

    T = 56972.17K

    Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa
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