Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.

V₂ = 2.96 L

Explanation:

Given dа ta:

Initial volume = 2.00 L

Initial temperature = 250°C

Final volume = ?

Final temperature = 500°C

Solution:

First of all we will convert the temperature into kelvin.

250+273 = 523 k

500+273 = 773 k

According to Charles's law,

V∝ T

V = KT

V₁/T₁ = V₂/T₂

V₂ = T₂V₁/T₁

V₂ = 2 L * 773 K / 523 k

V₂ = 1546 L. K / 523 k

V₂ = 2.96 L