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12 November, 03:35

Given the reaction: 2 Na (s) + Cl 2 (g) → 2 NaCl (s) The conversion factor for chlorine gas to sodium chloride is: 1 mol Cl 2 ≡ 2 mol NaCl. True or false?

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Answers (2)
  1. 12 November, 05:14
    0
    True

    Explanation:

    From the equation of reaction, one mole of chlorine gas molecule was consumed to produce two moles of sodium chloride
  2. 12 November, 06:02
    0
    Answer: True

    Explanation: The mole to mole ration is for 1 mole of Cl2 to produces 2 moles of NaCl. So the stoichiometric ratio is 1 is to 2.
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