Enter your answer in the provided box. Calculate the number of g of CO2 produced from the combustion of 5.24 mol of CzHg. The balanced equation is: C3H2 (g) + 502 (g) → 3CO2 (g) + 4H2O (g). g CO2

691.84g

Explanation:

I'm assuming that by CzHg, you mean C3H2

First, use the mole ratio in the equation to find the moles of CO2

n (CO2) = n (C3H2) * 3

= 5.24 * 3

= 15.72

To find the mass of CO2 produced in grams, complete the following calculation

m = n * MM

where

m = mass

n = moles

MM = molecular mass

m = 15.72 * (12.01 + (16*2))

m = 691.8372

m = 691.84g