Calculate the mass, in grams, of Avogadro's number of fluorine atoms. Enter your answer in the provided box. I g/mol

Every substance, whether an element or a compound that contains Avogadro's number, is said to form a mole of it. Therefore for the fluorine atoms that form the Avogadro number we say that we have one mole of fluorine atoms and this weighs 19 g, so 19 g/mol

Explanation:

You can search the F in the Periodic Table where you have the molar mass, 19 g/mol but if you don't have a Periodic Table you can calculate like this:

1 atom of F weighs 19 Da (unified atomic mass unit) and 1 Da is 1,661 x10*-24 g, so try to apply a rule of three, twice.

1 Da ... 1,661x10*-24 g

19 Da ... x

x = (19 Da. 1,661x10*-24 g) / 1 Da = 3,1559x10*-23 g

1 atom F ... 3,1559x10*-23 g

6,022x10*23 atoms F ... x

X = (6,022x10*23 atoms F. 3,1559x10*-23 g) / 1 atom F = 19.0048 g