How many grams do 6.7*1023 atoms of argon weigh?

44.4g

Explanation:

First we must find the moles of argon.

To do this, divide the number of atoms by Avogadro's number (6.022 * 10^23)

n = (6.7 * 10^23) / (6.022 * 10^23)

n=1.11258718034

Now to find mass, we complete the calculation

m = n * MM

where

m is mass

n is moles

MM is molecular mass

m = 1.11258718034 * 39.948

m = 44.4456326802

m = 44.4g